a(n)=16/3(3/2)^n-1

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Solution for a(n)=16/3(3/2)^n-1 equation: 


3;8;5;6;9;2

((3)*5)^(6)

3;8;5;6;19;2

2.8*(3-((1*i^2)/3))-1.9 = 0

(3*5)^(6)

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